Charles K. answered • 05/19/18

Retired College Professor Working With Students At All Levels

*m*=6 and

*r*=18. The solution set that has

*m*=-12 and

*r*=36 is incorrect. It doesn’t satisfy the terms of condition 1. Condition 1 states, “The distance between r and 0 is 3 times the distance between m and 0. Well, it turns out that when we write that out mathematically, we write,

*r*=3

*m*. Well, obviously 3(-12) is not equal to 36. We would have to use the absolute value when we set up to solve. Which is fine when using distance. But when we use absolute value we arrive at the same answer for both forms which is, m=6 and r=18. I repeat what I mentioned earlier in this note, the solution

*m*=-12 and

*r*=36 is incorrect. The following is the workout.

*r*= 3

*m*

*r*- 3

*m*= 0

*r*- 3

*m*| = 0

*r*- 3

*m*= 0 and

*r*+ 3

*m*= 0

*r*+

*m*= 24 (1)

*r*- 3

*m*= 0 (2)

*m*= 24

*m*= 6

*r*= 18.

*r*+ 3

*m*= 0) and solve the simultaneous equations.

*r*+

*m*= 24 (1)

*r*+ 3

*m*= 0 (2)

*m*= 24

*m*= 6

*r*= 18.

*m*= 6 and

*r*= 18. Any alternative solution does not meet the terms of the original equations in the setup.

Vinay J.

05/21/18

Sean S.

05/21/18